What is laplacetransform e^{j(2t+4)} ?

The answer to laplacetransform e^{j(2t+4)} is (e^{4j})/(s-2j)

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laplacetransform e^{j(2t+4)}

laplace transform

e^{j (2 t + 4)}

\frac{e ^{4 j}}{s - 2 j}

Solution steps

L {e^{j (2 t + 4)}}

Expand

e^{j (2 t + 4)} : e^{2 j t + 4 j}

= L {e^{2 j t + 4 j}}

Use the constant multiplication property of Laplace Transform:

For function

f (t)

and constant

a : L {a \cdot f (t)} = a \cdot L {f (t)}

= e^{4 j} L {e^{2 j t}}

L {e^{2 j t}} : \frac{1}{s - 2 j}

= e^{4 j} \frac{1}{s - 2 j}

Refine

e^{4 j} \frac{1}{s - 2 j} : \frac{e ^{4 j}}{s - 2 j}

= \frac{e ^{4 j}}{s - 2 j}

\frac{x ^{4}}{3}

\int 5 x^{4} - 1 d x

\frac{d}{d x} (\frac{5}{x ^{19}})

\int x^{2} + x - 2 d x

y = e^{\frac{1}{x}}

What is laplacetransform e^{j(2t+4)} ?
The answer to laplacetransform e^{j(2t+4)} is (e^{4j})/(s-2j)