What is the derivative of (x^3+1^5) ?

The derivative of (x^3+1^5) is 15x^2(x^3+1)^4

What is the first derivative of (x^3+1^5) ?

The first derivative of (x^3+1^5) is 15x^2(x^3+1)^4

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\frac{d}{d x} ((x^{3} + 1)^{5})

15 x^{2} (x^{3} + 1)^{4}

Solution steps

\frac{d}{d x} ((x^{3} + 1)^{5})

Apply the chain rule:

5 (x^{3} + 1)^{4} \frac{d}{d x} (x^{3} + 1)

= 5 (x^{3} + 1)^{4} \frac{d}{d x} (x^{3} + 1)

\frac{d}{d x} (x^{3} + 1) = 3 x^{2}

= 5 (x^{3} + 1)^{4} \cdot 3 x^{2}

Simplify

= 15 x^{2} (x^{3} + 1)^{4}

\frac{\partial}{\partial x} (e^{- \frac{1}{x}})

- 3 x^{2} y + y^{^{'}} = - 9 x^{2}

\int_{- 8}^{0} 2 + 64 - x^{2} d x

y = \frac{2}{x - 2}, (4, 1)

\frac{d}{d t} (t^{2} + t)

What is the derivative of (x^3+1^5) ?
The derivative of (x^3+1^5) is 15x^2(x^3+1)^4
What is the first derivative of (x^3+1^5) ?
The first derivative of (x^3+1^5) is 15x^2(x^3+1)^4