What is the sum from n=-infinity to infinity of 7^2 ?

The sum from n=-infinity to infinity of 7^2 is diverges

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sum from n=-infinity to infinity of 7^2

n = - \infty \sum \infty 7^{2}

diverges

Solution steps

n = - \infty \sum \infty 7^{2}

Every infinite sum of a non-zero constant diverges

= diverges

x \to 2 lim (\frac{3 x}{x - 4})

y^{^{''}} + 2 x = 0

\frac{\partial}{\partial x} (2 x^{2} y - x + 3 y^{3})

\frac{d}{d x} ((x - 2) (- x + 2) (x^{2} + 3 x - 3))

y^{^{''}} - 8 y^{^{'}} + 15 y = 0

What is the sum from n=-infinity to infinity of 7^2 ?
The sum from n=-infinity to infinity of 7^2 is diverges