What is the solution for (x^2+1)(dy)/(dx)+4x(y-1)=0,y(0)=8 ?

The solution for (x^2+1)(dy)/(dx)+4x(y-1)=0,y(0)=8 is y= 7/((x^2+1)^2)+1

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(x^2+1)(dy)/(dx)+4x(y-1)=0,y(0)=8

(x^{2} + 1) \frac{d y}{d x} + 4 x (y - 1) = 0, y (0) = 8

y = \frac{7}{( x ^{2} + 1 ) ^{2}} + 1

Solution steps

(x^{2} + 1) \frac{d y}{d x} + 4 x (y - 1) = 0

Solve separable ODE:

y = \frac{7}{( x ^{2} + 1 ) ^{2}} + 1

y = \frac{7}{( x ^{2} + 1 ) ^{2}} + 1

\int_{- 1}^{1} e^{y} - (y^{2} - 7) d y

\frac{d}{d x} (lo g_{9} (- (x - 4) (5 x - 2)))

\frac{\partial}{\partial y} (sin (x) y)

f (x) = \frac{x ^{5} + x ^{9}}{x}

y = 8 e^{- x} + e^{3 x}

What is the solution for (x^2+1)(dy)/(dx)+4x(y-1)=0,y(0)=8 ?
The solution for (x^2+1)(dy)/(dx)+4x(y-1)=0,y(0)=8 is y= 7/((x^2+1)^2)+1