What is (\partial)/(\partial x)(x^2y^3+(x-y)^2) ?

The answer to (\partial)/(\partial x)(x^2y^3+(x-y)^2) is 2y^3x+2(x-y)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial x)(x^2y^3+(x-y)^2)

\frac{\partial}{\partial x} (x^{2} y^{3} + (x - y)^{2})

2 y^{3} x + 2 (x - y)

Solution steps

\frac{\partial}{\partial x} (x^{2} y^{3} + (x - y)^{2})

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (x^{2} y^{3}) + \frac{\partial}{\partial x} ((x - y)^{2})

\frac{\partial}{\partial x} (x^{2} y^{3}) = 2 y^{3} x

\frac{\partial}{\partial x} ((x - y)^{2}) = 2 (x - y)

= 2 y^{3} x + 2 (x - y)

x y^{^{'}} + y = - 3 x y^{2}, y (1) = 4

\int 17 sin^{2} (2 x) d x

\int \frac{ln ( x )}{x ^{10}} d x

n = 3 \sum \infty cos (nπ)

1, 0 (1.0 3^{x})

What is (\partial)/(\partial x)(x^2y^3+(x-y)^2) ?
The answer to (\partial)/(\partial x)(x^2y^3+(x-y)^2) is 2y^3x+2(x-y)