What is the integral from 1 to 3 of (6x^2-4x+5) ?

The integral from 1 to 3 of (6x^2-4x+5) is 46

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 1 to 3 of (6x^2-4x+5)

\int_{1}^{3} (6 x^{2} - 4 x + 5) d x

46

Solution steps

\int_{1}^{3} 6 x^{2} - 4 x + 5 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{3} 6 x^{2} d x - \int_{1}^{3} 4 x d x + \int_{1}^{3} 5 d x

\int_{1}^{3} 6 x^{2} d x = 52

\int_{1}^{3} 4 x d x = 16

\int_{1}^{3} 5 d x = 10

= 52 - 16 + 10

Simplify

= 46

\int \frac{1}{3 + tan ^{2} ( x )} d x

\int_{0}^{\infty} e^{3 x} d x

x \to \infty lim ((x - 1)^{\frac{1}{l n ( x )}})

\frac{d}{d x} (e^{p (t, x) t} \cdot cos (n t))

\frac{\partial}{\partial x} (6 - x^{2} + 2 y^{2})

What is the integral from 1 to 3 of (6x^2-4x+5) ?
The integral from 1 to 3 of (6x^2-4x+5) is 46