What is the derivative of y=sin(tan(5x)) ?

The derivative of y=sin(tan(5x)) is cos(tan(5x))sec^2(5x)*5

What is the first derivative of y=sin(tan(5x)) ?

The first derivative of y=sin(tan(5x)) is cos(tan(5x))sec^2(5x)*5

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derivative of

y = sin (tan (5 x))

cos (tan (5 x)) sec^{2} (5 x) \cdot 5

Solution steps

\frac{d}{d x} (sin (tan (5 x)))

Apply the chain rule:

cos (tan (5 x)) \frac{d}{d x} (tan (5 x))

= cos (tan (5 x)) \frac{d}{d x} (tan (5 x))

\frac{d}{d x} (tan (5 x)) = sec^{2} (5 x) \cdot 5

= cos (tan (5 x)) sec^{2} (5 x) \cdot 5

\int (t^{9} + 4 t) (9 t^{8} + 4) d t

\int (4 x - \frac{2}{x}) d x

\int \frac{2}{( x - 3 ) ^{2}} d x

f (x) = x^{3} e^{- x^{3}} + 5

\int \frac{( x - 1 ) ( x ^{2} + 4 )}{x ( x + 1 )} d x

What is the derivative of y=sin(tan(5x)) ?
The derivative of y=sin(tan(5x)) is cos(tan(5x))sec^2(5x)*5
What is the first derivative of y=sin(tan(5x)) ?
The first derivative of y=sin(tan(5x)) is cos(tan(5x))sec^2(5x)*5