What is (\partial)/(\partial y)((x-2y)/(x+2)) ?

The answer to (\partial)/(\partial y)((x-2y)/(x+2)) is -2/(x+2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial y)((x-2y)/(x+2))

\frac{\partial}{\partial y} (\frac{x - 2 y}{x + 2})

- \frac{2}{x + 2}

Solution steps

\frac{\partial}{\partial y} (\frac{x - 2 y}{x + 2})

Treat

x

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{x + 2} \frac{\partial}{\partial y} (x - 2 y)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{1}{x + 2} (\frac{\partial}{\partial y} (x) - \frac{\partial}{\partial y} (2 y))

\frac{\partial}{\partial y} (x) = 0

\frac{\partial}{\partial y} (2 y) = 2

= \frac{1}{x + 2} (0 - 2)

Simplify

\frac{1}{x + 2} (0 - 2) : - \frac{2}{x + 2}

= - \frac{2}{x + 2}

\int_{0}^{3} π (3 x)^{2} d x

(6 + x) \frac{d y}{d x} = 9 y

\int (x ln (14 x)) d x

x \to 2 + lim (\frac{3 x ^{2}}{x - 2})

\int 8 sin^{4} (x) d x

What is (\partial)/(\partial y)((x-2y)/(x+2)) ?
The answer to (\partial)/(\partial y)((x-2y)/(x+2)) is -2/(x+2)