What is the integral of (sqrt(x))/(x^2) ?

The integral of (sqrt(x))/(x^2) is -2/(sqrt(x))+C

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integral of (sqrt(x))/(x^2)

\int \frac{x}{x ^{2}} d x

- \frac{2}{x} + C

Solution steps

\int \frac{x}{x ^{2}} d x

Simplify

\frac{x}{x ^{2}} : \frac{1}{x ^{\frac{3}{2}}}

= \int \frac{1}{x ^{\frac{3}{2}}} d x

Apply the Power Rule

: - \frac{2}{x}

= - \frac{2}{x}

Add a constant to the solution

= - \frac{2}{x} + C

x \to 0 lim (\frac{x}{cot ( 5 x )})

\int \frac{1}{1 + v ^{2}} d v

x \to 2 lim (- 4)

\int x e^{- x (1 + y)} d x

e^{2 t} t sin (5 t)

What is the integral of (sqrt(x))/(x^2) ?
The integral of (sqrt(x))/(x^2) is -2/(sqrt(x))+C