What is the d/(dt)(sqrt(1+t)) ?

The d/(dt)(sqrt(1+t)) is 1/(2sqrt(1+t))

What is the first d/(dt)(sqrt(1+t)) ?

The first d/(dt)(sqrt(1+t)) is 1/(2sqrt(1+t))

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\frac{d}{d t} (1 + t)

\frac{1}{2 1 + t}

Solution steps

\frac{d}{d t} (1 + t)

Apply the chain rule:

\frac{1}{2 1 + t} \frac{d}{d t} (1 + t)

= \frac{1}{2 1 + t} \frac{d}{d t} (1 + t)

\frac{d}{d t} (1 + t) = 1

= \frac{1}{2 1 + t} \cdot 1

Simplify

= \frac{1}{2 1 + t}

\frac{d y}{d t} = 2 t + y + 1

\int_{0}^{2 π} 2 x d x

y = x (x^{3} + 7)^{4}

\frac{\partial}{\partial x} (\frac{1}{2 x + 1})

n = 0 \sum \infty (- \frac{3}{5})^{n}

What is the d/(dt)(sqrt(1+t)) ?
The d/(dt)(sqrt(1+t)) is 1/(2sqrt(1+t))
What is the first d/(dt)(sqrt(1+t)) ?
The first d/(dt)(sqrt(1+t)) is 1/(2sqrt(1+t))