What is the derivative of tan(x+sec(x)) ?

The derivative of tan(x+sec(x)) is -1/(-1+sin(x))

What is the first derivative of tan(x+sec(x)) ?

The first derivative of tan(x+sec(x)) is -1/(-1+sin(x))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} (tan (x) + sec (x))

- \frac{1}{- 1 + sin ( x )}

Solution steps

\frac{d}{d x} (tan (x) + sec (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (tan (x)) + \frac{d}{d x} (sec (x))

\frac{d}{d x} (tan (x)) = sec^{2} (x)

\frac{d}{d x} (sec (x)) = sec (x) tan (x)

= sec^{2} (x) + sec (x) tan (x)

Simplify

sec^{2} (x) + sec (x) tan (x) : - \frac{1}{- 1 + sin ( x )}

= - \frac{1}{- 1 + sin ( x )}

x \to 6 - lim (x + 6)

\int sec (a x) tan (a x) d x

\int \frac{cot ^{2} ( 7 x )}{sec ( 7 x )} d x

\int ln (5 x + 4) d x

\frac{d}{d x} (\frac{1}{sin ( x )} + \frac{1}{cos ( x )})

What is the derivative of tan(x+sec(x)) ?
The derivative of tan(x+sec(x)) is -1/(-1+sin(x))
What is the first derivative of tan(x+sec(x)) ?
The first derivative of tan(x+sec(x)) is -1/(-1+sin(x))