What is the derivative of y=1+e^{-2x^2+8x-7} ?

The derivative of y=1+e^{-2x^2+8x-7} is e^{-2x^2+8x-7}(-4x+8)

What is the first derivative of y=1+e^{-2x^2+8x-7} ?

The first derivative of y=1+e^{-2x^2+8x-7} is e^{-2x^2+8x-7}(-4x+8)

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derivative of

y = 1 + e^{- 2 x^{2} + 8 x - 7}

e^{- 2 x^{2} + 8 x - 7} (- 4 x + 8)

Solution steps

\frac{d}{d x} (1 + e^{- 2 x^{2} + 8 x - 7})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (1) + \frac{d}{d x} (e^{- 2 x^{2} + 8 x - 7})

\frac{d}{d x} (1) = 0

\frac{d}{d x} (e^{- 2 x^{2} + 8 x - 7}) = e^{- 2 x^{2} + 8 x - 7} (- 4 x + 8)

= 0 + e^{- 2 x^{2} + 8 x - 7} (- 4 x + 8)

Simplify

= e^{- 2 x^{2} + 8 x - 7} (- 4 x + 8)

x \to 0 lim (- (\frac{1}{x ^{2}}))

y^{^{'}} = 9 t y^{2}

x \to - 4 - lim (\frac{∣ x + 4 ∣}{x + 4})

y^{^{''}} + 23 y = 0

\frac{d y}{d x} = 1 + e^{2 x}

What is the derivative of y=1+e^{-2x^2+8x-7} ?
The derivative of y=1+e^{-2x^2+8x-7} is e^{-2x^2+8x-7}(-4x+8)
What is the first derivative of y=1+e^{-2x^2+8x-7} ?
The first derivative of y=1+e^{-2x^2+8x-7} is e^{-2x^2+8x-7}(-4x+8)