What is the tangent of y= 1/(x^2),(-2, 1/4) ?

The tangent of y= 1/(x^2),(-2, 1/4) is y= 1/4 x+3/4

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tangent of y= 1/(x^2),(-2, 1/4)

tangent of

y = \frac{1}{x ^{2}}, (- 2, \frac{1}{4})

y = \frac{1}{4} x + \frac{3}{4}

Solution steps

Find the slope of

y = \frac{1}{x ^{2}} : \frac{d y}{d x} = - \frac{2}{x ^{3}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = \frac{1}{4}

Find the line with slope m=

\frac{1}{4}

and passing through

(- 2, \frac{1}{4}) : y = \frac{1}{4} x + \frac{3}{4}

y = \frac{1}{4} x + \frac{3}{4}

x \to - \infty lim (3^{5 x})

\int \frac{sin ^{3} ( x )}{cos ^{6} ( x )} d x

y = 3 + 4 x^{2} - 2 x^{3}, at x = a

x \to \infty lim ((\frac{1}{x})^{\frac{2}{x}})

y^{^{''}} + 5 t y^{^{'}} - 5 y = 0

What is the tangent of y= 1/(x^2),(-2, 1/4) ?
The tangent of y= 1/(x^2),(-2, 1/4) is y= 1/4 x+3/4