What is the tangent of f(x)=6tan(x) ?

The tangent of f(x)=6tan(x) is y=6sec^2(a_{0})x+6tan(a_{0})-6sec^2(a_{0})a_{0}

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tangent of f(x)=6tan(x)

tangent of

f (x) = 6 tan (x)

y = 6 sec^{2} (a_{0}) x + 6 tan (a_{0}) - 6 sec^{2} (a_{0}) a_{0}

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, 6 tan (a_{0}))

Find the slope of

f (x) = 6 tan (x) : \frac{df ( x )}{d x} = 6 sec^{2} (x)

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 6 sec^{2} (a_{0})

Find the line with slope m=

6 sec^{2} (a_{0})

and passing through

(a_{0}, 6 tan (a_{0})) : y = 6 sec^{2} (a_{0}) x + 6 tan (a_{0}) - 6 sec^{2} (a_{0}) a_{0}

y = 6 sec^{2} (a_{0}) x + 6 tan (a_{0}) - 6 sec^{2} (a_{0}) a_{0}

x \to 2 lim (\frac{1}{( x - 2 ) ^{2}})

w (z) = 6 z^{2} e^{z}

\int_{0}^{l n (2)} \int_{1}^{l n (5)} e^{2 x + y} d y d x

\frac{d}{d x} (\frac{1 - x}{( x + 1 ) ^{3}})

sin (2 x) d x + cos (7 y) d y = 0, y (\frac{π}{2}) = \frac{π}{7}

What is the tangent of f(x)=6tan(x) ?
The tangent of f(x)=6tan(x) is y=6sec^2(a_{0})x+6tan(a_{0})-6sec^2(a_{0})a_{0}