What is the limit as x approaches 1 of e^{5x^4-5x} ?

The limit as x approaches 1 of e^{5x^4-5x} is 1

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limit as x approaches 1 of e^{5x^4-5x}

x \to 1 lim (e^{5 x^{4} - 5 x})

1

Solution steps

x \to 1 lim (e^{5 x^{4} - 5 x})

Plug in the value

x = 1

= e^{5 \cdot 1^{4} - 5 \cdot 1}

Simplify

= 1

\frac{\partial}{\partial x} (x^{3} y + z^{2} x - z y^{2})

x \to 0 lim (\frac{( sin ( 5 x ) )}{x})

\int \frac{cos ( t )}{t} d t

\frac{d y}{d x} = x (y - 1)^{2}

y = (x^{3} - 16 x)^{10}, (4, 0)

What is the limit as x approaches 1 of e^{5x^4-5x} ?
The limit as x approaches 1 of e^{5x^4-5x} is 1