What is the derivative of sqrt(2x)+sqrt(y) ?

The derivative of sqrt(2x)+sqrt(y) is 1/(sqrt(2)\sqrt{x)}

What is the first derivative of sqrt(2x)+sqrt(y) ?

The first derivative of sqrt(2x)+sqrt(y) is 1/(sqrt(2)\sqrt{x)}

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derivative of

2 x + y

\frac{1}{2 x}

Solution steps

\frac{d}{d x} (2 x + y)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x) + \frac{d}{d x} (y)

\frac{d}{d x} (2 x) = \frac{1}{2 x}

\frac{d}{d x} (y) = 0

= \frac{1}{2 x} + 0

Simplify

= \frac{1}{2 x}

x \to 6 - lim (\frac{7}{x - 6})

(4 x^{2} + 3 y^{2}) d x - (2 x y) d y = 0

y = x^{2} - 4

\frac{d}{d x} (4^{- 3} (\frac{2}{x ^{7}} + 3 x)^{4})

\frac{d}{d x} ((9 x + 4) x^{2})

What is the derivative of sqrt(2x)+sqrt(y) ?
The derivative of sqrt(2x)+sqrt(y) is 1/(sqrt(2)\sqrt{x)}
What is the first derivative of sqrt(2x)+sqrt(y) ?
The first derivative of sqrt(2x)+sqrt(y) is 1/(sqrt(2)\sqrt{x)}