What is the integral of-2x^2+4x+6 ?

The integral of-2x^2+4x+6 is -(2x^3)/3+2x^2+6x+C

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integral of-2x^2+4x+6

\int - 2 x^{2} + 4 x + 6 d x

- \frac{2 x ^{3}}{3} + 2 x^{2} + 6 x + C

Solution steps

\int - 2 x^{2} + 4 x + 6 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int 2 x^{2} d x + \int 4 x d x + \int 6 d x

\int 2 x^{2} d x = \frac{2 x ^{3}}{3}

\int 4 x d x = 2 x^{2}

\int 6 d x = 6 x

= - \frac{2 x ^{3}}{3} + 2 x^{2} + 6 x

Add a constant to the solution

= - \frac{2 x ^{3}}{3} + 2 x^{2} + 6 x + C

\int_{0}^{1} e^{- 0.1 x} d x

y = e^{2} x

\frac{d}{d z} (x^{2} + y^{2} + z^{2})

\int \frac{( x ^{3} + 1 ) ^{2}}{x ^{2}} d x

\frac{d}{d x} y = sec (2 x)

What is the integral of-2x^2+4x+6 ?
The integral of-2x^2+4x+6 is -(2x^3)/3+2x^2+6x+C