What is the tangent of f(x)=2xsqrt(x-2),\at x=3 ?

The tangent of f(x)=2xsqrt(x-2),\at x=3 is y=5x-9

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tangent of f(x)=2xsqrt(x-2),\at x=3

tangent of

f (x) = 2 x x - 2, at x = 3

y = 5 x - 9

Solution steps

Find the tangent point:

(3, 6)

Find the slope of

f (x) = 2 x x - 2 : \frac{df ( x )}{d x} = \frac{3 x - 4}{x - 2}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 5

Find the line with slope m=

5

and passing through

(3, 6) : y = 5 x - 9

y = 5 x - 9

∣ 10 x ∣, x^{2} - 11

x \to 4 lim ((x^{2} - 8) (4 x - 8))

\frac{\partial}{\partial y} (cos (x) cosh (y))

\frac{\partial}{\partial x} (sin (x + t))

x \to - 9 + lim (\frac{1}{( x + 9 ) ^{2}})

What is the tangent of f(x)=2xsqrt(x-2),\at x=3 ?
The tangent of f(x)=2xsqrt(x-2),\at x=3 is y=5x-9