What is the integral of 10sin(x)-2cos(x) ?

The integral of 10sin(x)-2cos(x) is -10cos(x)-2sin(x)+C

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integral of 10sin(x)-2cos(x)

\int 10 sin (x) - 2 cos (x) d x

- 10 cos (x) - 2 sin (x) + C

Solution steps

\int 10 sin (x) - 2 cos (x) d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 10 sin (x) d x - \int 2 cos (x) d x

\int 10 sin (x) d x = - 10 cos (x)

\int 2 cos (x) d x = 2 sin (x)

= - 10 cos (x) - 2 sin (x)

Add a constant to the solution

= - 10 cos (x) - 2 sin (x) + C

\int 6 y^{2} d y

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\int cosh (x) sin (d) x d x

\int \frac{1}{( x - 2 )} d x

\frac{e ^{- 7 s}}{( s ^{2} - 25 )}

What is the integral of 10sin(x)-2cos(x) ?
The integral of 10sin(x)-2cos(x) is -10cos(x)-2sin(x)+C