What is area y=3x^3-x^2-10x,y=-x^2+2x ?

The answer to area y=3x^3-x^2-10x,y=-x^2+2x is 24

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area y=3x^3-x^2-10x,y=-x^2+2x

area

y = 3 x^{3} - x^{2} - 10 x, y = - x^{2} + 2 x

24

Solution steps

Apply the area formula:

\int_{- 2}^{2} 3 x^{3} - x^{2} - 10 x - (- x^{2} + 2 x) d x

Solve

\int_{- 2}^{2} 3 x^{3} - x^{2} - 10 x - (- x^{2} + 2 x) d x : 24

The area is:

= 24

\frac{d}{d x} (\frac{6}{( x - 1 ) ^{2}})

f (x) = 6 cos (x) + 3 sin (2 x)

y^{^{''}} - y^{^{'}} - 2 y = 0, y (0) = 2, y^{^{'}} (0) = 2

\frac{\partial}{\partial x} (1 + 3 x)

x \cdot d y = (x + y) \cdot d x

What is area y=3x^3-x^2-10x,y=-x^2+2x ?
The answer to area y=3x^3-x^2-10x,y=-x^2+2x is 24