What is the solution for (dy}{dx}=\frac{(1+y))/x ?

The solution for (dy}{dx}=\frac{(1+y))/x is y=c_{1}x-1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(dy}{dx}=\frac{(1+y))/x

\frac{d y}{d x} = \frac{( 1 + y )}{x}

y = c_{1} x - 1

Solution steps

\frac{d y}{d x} = \frac{( 1 + y )}{x}

Solve separable ODE:

y = c_{1} x - 1

y = c_{1} x - 1

(0.2) (1.5)

x \to 0 lim (\frac{2}{3 x ^{\frac{1}{3}}})

x

\int x ln (x^{2} + 1) + (x^{2} + 1) y d x

\int \frac{1}{5 - x ^{2}} d x

What is the solution for (dy}{dx}=\frac{(1+y))/x ?
The solution for (dy}{dx}=\frac{(1+y))/x is y=c_{1}x-1