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Popular >

xy^'+y=xy^2

Solution

x y^{^{'}} + y = x y^{2}

Solution

y = \frac{1}{x ( - ln ( x ) + c _{1} )}

Solution steps

x y^{'} (x) + y = x y^{2}

Solve Bernoulli ODE:

y = \frac{1}{x ( - ln ( x ) + c _{1} )}

y = \frac{1}{x ( - ln ( x ) + c _{1} )}

Graph

Popular Examples

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\int (5 - 3 x^{2}) ln (x) d x

f(x)=arctan(x^2)

f (x) = arctan (x^{2})

derivative of (x^5)/5+1/(12x^3)derivative of

\frac{x ^{5}}{5} + \frac{1}{12 x ^{3}}

integral of (3x^5)/(sqrt(1-6x^6))

\int \frac{3 x ^{5}}{1 - 6 x ^{6}} d x

Frequently Asked Questions (FAQ)

What is the solution for xy^'+y=xy^2 ?
The solution for xy^'+y=xy^2 is y= 1/(x(-ln(x)+c_{1))}