What is the solution for (dy)/(dx)=32x^3y^3 ?

The solution for (dy)/(dx)=32x^3y^3 is y=sqrt(-1/(2(8x^4+c_{1)))},y=-sqrt(-1/(2(8x^4+c_{1)))}

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(dy)/(dx)=32x^3y^3

\frac{d y}{d x} = 32 x^{3} y^{3}

y = - \frac{1}{2 ( 8 x ^{4} + c _{1} )}, y = - - \frac{1}{2 ( 8 x ^{4} + c _{1} )}

Solution steps

\frac{d y}{d x} = 32 x^{3} y^{3}

Solve separable ODE:

y = - \frac{1}{2 ( 8 x ^{4} + c _{1} )}, y = - - \frac{1}{2 ( 8 x ^{4} + c _{1} )}

y = - \frac{1}{2 ( 8 x ^{4} + c _{1} )}, y = - - \frac{1}{2 ( 8 x ^{4} + c _{1} )}

x \to 0 lim ((1 - \frac{1}{2 x})^{x})

\frac{d}{d y} (y e^{x} + 2 e^{x} + y^{2})

\int (2 x + 1)^{5} d x

\frac{- 2}{( s ^{2} + 1 ) ^{2}}

\int_{0}^{π} sin^{4} (3 t) d t

What is the solution for (dy)/(dx)=32x^3y^3 ?
The solution for (dy)/(dx)=32x^3y^3 is y=sqrt(-1/(2(8x^4+c_{1)))},y=-sqrt(-1/(2(8x^4+c_{1)))}