What is the derivative of f(x)=(6x^2+4x)^2 ?

The derivative of f(x)=(6x^2+4x)^2 is 2(6x^2+4x)(12x+4)

What is the first derivative of f(x)=(6x^2+4x)^2 ?

The first derivative of f(x)=(6x^2+4x)^2 is 2(6x^2+4x)(12x+4)

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derivative of

f (x) = (6 x^{2} + 4 x)^{2}

2 (6 x^{2} + 4 x) (12 x + 4)

Solution steps

\frac{d}{d x} ((6 x^{2} + 4 x)^{2})

Apply the chain rule:

2 (6 x^{2} + 4 x) \frac{d}{d x} (6 x^{2} + 4 x)

= 2 (6 x^{2} + 4 x) \frac{d}{d x} (6 x^{2} + 4 x)

\frac{d}{d x} (6 x^{2} + 4 x) = 12 x + 4

= 2 (6 x^{2} + 4 x) (12 x + 4)

1100 + 13 x - 0.1 x^{2} + 0.0005 x^{3}

\int \frac{- ( 4 x + 10 )}{x ^{3}} d x

x = \frac{( y - 3 ) ^{2}}{5}, y = 13 - x

\int + \frac{13}{( t ^{2} + 1 ) ^{\frac{3}{2}}} d t

x \to 1 lim (\frac{1}{x})

What is the derivative of f(x)=(6x^2+4x)^2 ?
The derivative of f(x)=(6x^2+4x)^2 is 2(6x^2+4x)(12x+4)
What is the first derivative of f(x)=(6x^2+4x)^2 ?
The first derivative of f(x)=(6x^2+4x)^2 is 2(6x^2+4x)(12x+4)