What is the solution for 2(12)(5)+2(5)(dy)/(dt)=0 ?

The solution for 2(12)(5)+2(5)(dy)/(dt)=0 is y=-12t+c_{1}

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2(12)(5)+2(5)(dy)/(dt)=0

2 (12) (5) + 2 (5) \frac{d y}{d t} = 0

y = - 12 t + c_{1}

Solution steps

2 (12) (5) + 2 (5) \frac{d y}{d t} = 0

Substitute

\frac{d y}{d t}

with

y^{'} (t)

2 (12) (5) + 2 (5) y^{^{'}} (t) = 0

Isolate

y^{'} (t) : y^{'} (t) = - 12

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

y = \int - 12 d t

\int - 12 d t = - 12 t + c_{1}

y = - 12 t + c_{1}

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What is the solution for 2(12)(5)+2(5)(dy)/(dt)=0 ?
The solution for 2(12)(5)+2(5)(dy)/(dt)=0 is y=-12t+c_{1}