What is the d/(dy)(ln(y)-(y^2)/8) ?

The d/(dy)(ln(y)-(y^2)/8) is 1/y-y/4

What is the first d/(dy)(ln(y)-(y^2)/8) ?

The first d/(dy)(ln(y)-(y^2)/8) is 1/y-y/4

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\frac{d}{d y} (ln (y) - \frac{y ^{2}}{8})

\frac{1}{y} - \frac{y}{4}

Solution steps

\frac{d}{d y} (ln (y) - \frac{y ^{2}}{8})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d y} (ln (y)) - \frac{d}{d y} (\frac{y ^{2}}{8})

\frac{d}{d y} (ln (y)) = \frac{1}{y}

\frac{d}{d y} (\frac{y ^{2}}{8}) = \frac{y}{4}

= \frac{1}{y} - \frac{y}{4}

\int cos (4 x) d x

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\frac{2}{s ^{2} + 3 s - 4}

\frac{1}{3} t - 2 (1 - e^{- \frac{t}{4}})

π sin (2 π x)

What is the d/(dy)(ln(y)-(y^2)/8) ?
The d/(dy)(ln(y)-(y^2)/8) is 1/y-y/4
What is the first d/(dy)(ln(y)-(y^2)/8) ?
The first d/(dy)(ln(y)-(y^2)/8) is 1/y-y/4