What is the derivative of (x+4)(x-5)^2 ?

The derivative of (x+4)(x-5)^2 is 3x^2-12x-15

What is the first derivative of (x+4)(x-5)^2 ?

The first derivative of (x+4)(x-5)^2 is 3x^2-12x-15

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derivative of

(x + 4) (x - 5)^{2}

3 x^{2} - 12 x - 15

Solution steps

\frac{d}{d x} ((x + 4) (x - 5)^{2})

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x + 4, g = (x - 5)^{2}

= \frac{d}{d x} (x + 4) (x - 5)^{2} + \frac{d}{d x} ((x - 5)^{2}) (x + 4)

\frac{d}{d x} (x + 4) = 1

\frac{d}{d x} ((x - 5)^{2}) = 2 (x - 5)

= 1 \cdot (x - 5)^{2} + 2 (x - 5) (x + 4)

Simplify

1 \cdot (x - 5)^{2} + 2 (x - 5) (x + 4) : 3 x^{2} - 12 x - 15

= 3 x^{2} - 12 x - 15

\frac{s + 1}{( s + 2 ) ( s + 6 ) ^{2}}

f (x) = x^{3} - 2 x + 7, at x = - 2

x^{4} - 2 x^{2} + 5

n = 1 \sum \infty 8 e^{- 6 n}

\frac{y ^{^{'}} - e ^{- t} + 4}{y} = - 4

What is the derivative of (x+4)(x-5)^2 ?
The derivative of (x+4)(x-5)^2 is 3x^2-12x-15
What is the first derivative of (x+4)(x-5)^2 ?
The first derivative of (x+4)(x-5)^2 is 3x^2-12x-15