What is the solution for sin(xy)dx=2xdy+2ydx ?

The solution for sin(xy)dx=2xdy+2ydx is y=(2arctan(e^{(x+c_{1})/2}))/(x)+(2pin)/x

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sin(xy)dx=2xdy+2ydx

sin (x y) d x = 2 x d y + 2 y d x

y = \frac{2 arctan ( e ^{\frac{x + c _{1}}{2}} )}{x} + \frac{2 πn}{x}

Solution steps

sin (x y) d x = 2 x d y + 2 y d x

Solve using substitution:

y = \frac{2 arctan ( e ^{\frac{x + c _{1}}{2}} )}{x} + \frac{2 πn}{x}

y = \frac{2 arctan ( e ^{\frac{x + c _{1}}{2}} )}{x} + \frac{2 πn}{x}

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What is the solution for sin(xy)dx=2xdy+2ydx ?
The solution for sin(xy)dx=2xdy+2ydx is y=(2arctan(e^{(x+c_{1})/2}))/(x)+(2pin)/x