What is the integral of sin(t)k ?

The integral of sin(t)k is -kcos(t)+C

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integral of sin(t)k

\int sin (t) k d t

- k cos (t) + C

Solution steps

\int sin (t) k d t

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= k \cdot \int sin (t) d t

Use the common integral:

\int sin (t) d t = - cos (t)

= k (- cos (t))

Simplify

= - k cos (t)

Add a constant to the solution

= - k cos (t) + C

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