en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^'=x^2*(1+y)

Solution

y^{^{'}} = x^{2} \cdot (1 + y)

Solution

y = e^{\frac{x ^{3}}{3} + c_{1}} - 1

Solution steps

y^{'} (x) = x^{2} \cdot (1 + y)

Solve separable ODE:

y = e^{\frac{x ^{3}}{3} + c_{1}} - 1

y = e^{\frac{x ^{3}}{3} + c_{1}} - 1

Graph

Popular Examples

sum from n=1 to infinity of n(1/2)^n

n = 1 \sum \infty n (\frac{1}{2})^{n}

integral of cos(3x)e^{2x}

\int cos (3 x) e^{2 x} d x

derivative of f(x)=x^5e^{8x}derivative of

f (x) = x^{5} e^{8 x}

y^{''}+2y^'+y=3e^{-t}

y^{^{''}} + 2 y^{^{'}} + y = 3 e^{- t}

integral of x^2*5^x

\int x^{2} \cdot 5^{x} d x

Frequently Asked Questions (FAQ)

What is the solution for y^'=x^2*(1+y) ?
The solution for y^'=x^2*(1+y) is y=e^{(x^3)/3+c_{1}}-1