What is the derivative of 1/3 pih^2(3r-h) ?

The derivative of 1/3 pih^2(3r-h) is pih^2

What is the first derivative of 1/3 pih^2(3r-h) ?

The first derivative of 1/3 pih^2(3r-h) is pih^2

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derivative of

\frac{1}{3} π h^{2} (3 r - h)

π h^{2}

Solution steps

\frac{d}{d r} (\frac{1}{3} π h^{2} (3 r - h))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{3} π h^{2} \frac{d}{d r} (3 r - h)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{1}{3} π h^{2} (\frac{d}{d r} (3 r) - \frac{d h}{d r})

\frac{d}{d r} (3 r) = 3

\frac{d h}{d r} = 0

= \frac{1}{3} π h^{2} (3 - 0)

Simplify

\frac{1}{3} π h^{2} (3 - 0) : π h^{2}

= π h^{2}

\int_{0}^{3} x^{5} 2 x^{3} + 1 d x

\frac{d}{d x} (5^{2 x + 1})

y^{^{''}} - 2 y^{^{'}} + y = \frac{( e ^{t} )}{1 + t ^{2}}

x \to 0 - lim (12 e^{- \frac{2}{x}})

f (x) = \frac{x ^{2} - 1}{x ^{2} + x + 1}

What is the derivative of 1/3 pih^2(3r-h) ?
The derivative of 1/3 pih^2(3r-h) is pih^2
What is the first derivative of 1/3 pih^2(3r-h) ?
The first derivative of 1/3 pih^2(3r-h) is pih^2