What is the tangent of f(x)=sqrt(2-7x),(-2,4) ?

The tangent of f(x)=sqrt(2-7x),(-2,4) is y=-7/8 x+9/4

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tangent of f(x)=sqrt(2-7x),(-2,4)

tangent of

f (x) = 2 - 7 x, (- 2, 4)

y = - \frac{7}{8} x + \frac{9}{4}

Solution steps

Find the slope of

f (x) = 2 - 7 x : \frac{df ( x )}{d x} = - \frac{7}{2 2 - 7 x}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - \frac{7}{8}

Find the line with slope m=

- \frac{7}{8}

and passing through

(- 2, 4) : y = - \frac{7}{8} x + \frac{9}{4}

y = - \frac{7}{8} x + \frac{9}{4}

\frac{d}{d x} (∣ cos (x) ∣)

(y^{3} - 1) e^{x} d x + 3 y^{2} (e^{x} + 1) d y = 0, y (0) = - 2

\int 3 x^{2} + 5 d x

\frac{\partial}{\partial x} (9 - x^{3} - y^{5})

\frac{d}{d x} (6^{4 - 3 x})

What is the tangent of f(x)=sqrt(2-7x),(-2,4) ?
The tangent of f(x)=sqrt(2-7x),(-2,4) is y=-7/8 x+9/4