What is (\partial)/(\partial y)(xy-2y) ?

The answer to (\partial)/(\partial y)(xy-2y) is x-2

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(\partial)/(\partial y)(xy-2y)

\frac{\partial}{\partial y} (x y - 2 y)

x - 2

Solution steps

\frac{\partial}{\partial y} (x y - 2 y)

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (x y) - \frac{\partial}{\partial y} (2 y)

\frac{\partial}{\partial y} (x y) = x

\frac{\partial}{\partial y} (2 y) = 2

= x - 2

f (x) g (x) h (x)

2 x^{2} + 8

f (x) = 6 e^{x} + 5 x - ln (x)

\int (x^{3} + 3) x^{2} d x

\frac{d}{d x} (y^{2} (6 - 2 x))

What is (\partial)/(\partial y)(xy-2y) ?
The answer to (\partial)/(\partial y)(xy-2y) is x-2