What is the derivative of (5x-7/(6x-9)) ?

The derivative of (5x-7/(6x-9)) is -1/(3(2x-3)^2)

What is the first derivative of (5x-7/(6x-9)) ?

The first derivative of (5x-7/(6x-9)) is -1/(3(2x-3)^2)

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\frac{d}{d x} (\frac{5 x - 7}{6 x - 9})

- \frac{1}{3 ( 2 x - 3 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{5 x - 7}{6 x - 9})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( 5 x - 7 ) ( 6 x - 9 ) - \frac{d}{d x} ( 6 x - 9 ) ( 5 x - 7 )}{( 6 x - 9 ) ^{2}}

\frac{d}{d x} (5 x - 7) = 5

\frac{d}{d x} (6 x - 9) = 6

= \frac{5 ( 6 x - 9 ) - 6 ( 5 x - 7 )}{( 6 x - 9 ) ^{2}}

Simplify

\frac{5 ( 6 x - 9 ) - 6 ( 5 x - 7 )}{( 6 x - 9 ) ^{2}} : - \frac{1}{3 ( 2 x - 3 ) ^{2}}

= - \frac{1}{3 ( 2 x - 3 ) ^{2}}

\int x^{14} e^{x^{15}} d x

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y = - (x - 2)^{2} + 16

\int \frac{8 x + 28}{x ^{2} + 8 x + 12} d x

What is the derivative of (5x-7/(6x-9)) ?
The derivative of (5x-7/(6x-9)) is -1/(3(2x-3)^2)
What is the first derivative of (5x-7/(6x-9)) ?
The first derivative of (5x-7/(6x-9)) is -1/(3(2x-3)^2)