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Popular >

y^'=(y^2+1)/x

Solution

y^{^{'}} = \frac{y ^{2} + 1}{x}

Solution

y = tan (ln (x) + c_{1})

Solution steps

y^{'} (x) = \frac{y ^{2} + 1}{x}

Solve separable ODE:

y = tan (ln (x) + c_{1})

y = tan (ln (x) + c_{1})

Graph

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Frequently Asked Questions (FAQ)

What is the solution for y^'=(y^2+1)/x ?
The solution for y^'=(y^2+1)/x is y=tan(ln(x)+c_{1})