What is the derivative of f(x)=8x+ln(x^2) ?

The derivative of f(x)=8x+ln(x^2) is 8+2/x

What is the first derivative of f(x)=8x+ln(x^2) ?

The first derivative of f(x)=8x+ln(x^2) is 8+2/x

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derivative of

f (x) = 8 x + ln (x^{2})

8 + \frac{2}{x}

Solution steps

\frac{d}{d x} (8 x + ln (x^{2}))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (8 x) + \frac{d}{d x} (ln (x^{2}))

\frac{d}{d x} (8 x) = 8

\frac{d}{d x} (ln (x^{2})) = \frac{2}{x}

= 8 + \frac{2}{x}

\int (5 x^{3} + 6)^{4} x^{2} d x

y^{^{'}} - y = 5 t e^{2 t}, y (0) = 1

n = 0 \sum \infty (1.075)^{n}

y = x + 1, (0, 2)

7 x^{3} - 6 x + \frac{3}{x ^{7}} + 9

What is the derivative of f(x)=8x+ln(x^2) ?
The derivative of f(x)=8x+ln(x^2) is 8+2/x
What is the first derivative of f(x)=8x+ln(x^2) ?
The first derivative of f(x)=8x+ln(x^2) is 8+2/x