What is the integral of cos(-2x) ?

The integral of cos(-2x) is 1/2 sin(2x)+C

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integral of cos(-2x)

\int cos (- 2 x) d x

\frac{1}{2} sin (2 x) + C

Solution steps

\int cos (- 2 x) d x

Apply u-substitution

: \int - \frac{1}{2} cos (u) d u

= \int - \frac{1}{2} cos (u) d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \frac{1}{2} \cdot \int cos (u) d u

Use the common integral:

\int cos (u) d u = sin (u)

= - \frac{1}{2} sin (u)

Substitute back

u = - 2 x

= - \frac{1}{2} sin (- 2 x)

Simplify

- \frac{1}{2} sin (- 2 x) : \frac{1}{2} sin (2 x)

= \frac{1}{2} sin (2 x)

Add a constant to the solution

= \frac{1}{2} sin (2 x) + C

\frac{d x}{d t} + x = 3 e^{t}

y^{^{'}} - y = e^{3 x}

f (x) = 11 x^{4} cot (x)

\frac{d}{d x} (x (5 x + 1)^{\frac{1}{3}})

\frac{1}{x}, 1, 4