What is the tangent of y=4x*tan(x),\at x=pi ?

The tangent of y=4x*tan(x),\at x=pi is y=4pix-4pi^2

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tangent of y=4x*tan(x),\at x=pi

tangent of

y = 4 x \cdot tan (x), at x = π

y = 4 π x - 4 π^{2}

Solution steps

Find the tangent point:

(π, 0)

Find the slope of

y = 4 x tan (x) : \frac{d y}{d x} = 4 (tan (x) + x sec^{2} (x))

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 4 π

Find the line with slope m=

4 π

and passing through

(π, 0) : y = 4 π x - 4 π^{2}

y = 4 π x - 4 π^{2}

\int 4 sin (x) d x

\frac{d y}{d t} = 7 t e^{2 y}

\frac{\partial}{\partial x} (0.5 x arctan (\frac{y}{x}))

\int x^{2} sin (\frac{x}{2}) d x

\int \frac{1 + x}{x} d x

What is the tangent of y=4x*tan(x),\at x=pi ?
The tangent of y=4x*tan(x),\at x=pi is y=4pix-4pi^2