What is the integral from 0 to 3 of (1/(x^2)) ?

The integral from 0 to 3 of (1/(x^2)) is diverges

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integral from 0 to 3 of (1/(x^2))

\int_{0}^{3} (\frac{1}{x ^{2}}) d x

diverges

Solution steps

\int_{0}^{3} \frac{1}{x ^{2}} d x

Apply the Power Rule

: [- \frac{1}{x}]_{0}^{3}

= [- \frac{1}{x}]_{0}^{3}

Compute the boundaries:

diverges

= diverges

x \to 2 lim (x^{2} - 8)

\frac{d}{d x} (- \frac{1}{4} x^{- \frac{3}{2}})

\frac{d}{d x} (\frac{x ^{2} - 3 x + 2}{- x ^{2} - 4 x + 4})

3 x^{2} + 4

x \to 0 lim (\frac{( e ^{x} - e ^{- x} - 2 x )}{( x - sin ( x ) )})

What is the integral from 0 to 3 of (1/(x^2)) ?
The integral from 0 to 3 of (1/(x^2)) is diverges