What is the derivative of (2x-1^4) ?

The derivative of (2x-1^4) is 8(2x-1)^3

What is the first derivative of (2x-1^4) ?

The first derivative of (2x-1^4) is 8(2x-1)^3

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\frac{d}{d x} ((2 x - 1)^{4})

8 (2 x - 1)^{3}

Solution steps

\frac{d}{d x} ((2 x - 1)^{4})

Apply the chain rule:

4 (2 x - 1)^{3} \frac{d}{d x} (2 x - 1)

= 4 (2 x - 1)^{3} \frac{d}{d x} (2 x - 1)

\frac{d}{d x} (2 x - 1) = 2

= 4 (2 x - 1)^{3} \cdot 2

Simplify

= 8 (2 x - 1)^{3}

\frac{d}{d q} (- q^{2} + 36)

\frac{s + 2}{( s + 3 ) ^{2} ( s - 1 )}

x \to 0 - lim (\frac{3}{1 + e ^{\frac{1}{x}}})

\int x (7 - x)^{2} d x

1 + x

What is the derivative of (2x-1^4) ?
The derivative of (2x-1^4) is 8(2x-1)^3
What is the first derivative of (2x-1^4) ?
The first derivative of (2x-1^4) is 8(2x-1)^3