What is the solution for (dy)/(dx)+y/x =y^{-2} ?

The solution for (dy)/(dx)+y/x =y^{-2} is y=(\sqrt[3]{3x^4+c_{1}})/(\sqrt[3]{4)x}

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(dy)/(dx)+y/x =y^{-2}

\frac{d y}{d x} + \frac{y}{x} = y^{- 2}

y = \frac{3 3 x ^{4} + c _{1}}{3 4 x}

Solution steps

\frac{d y}{d x} + \frac{y}{x} = y^{- 2}

Solve Bernoulli ODE:

y = \frac{3 3 x ^{4} + c _{1}}{3 4 x}

y = \frac{3 3 x ^{4} + c _{1}}{3 4 x}

\frac{( t ^{3} + t )}{( t ^{4} - 2 )}

y^{^{'}} + e^{x} y = y^{2}

\frac{1 - 4 x}{1 + 4 x}

y = - 3 x - 5

\frac{d}{d y} (1 - y)

What is the solution for (dy)/(dx)+y/x =y^{-2} ?
The solution for (dy)/(dx)+y/x =y^{-2} is y=(\sqrt[3]{3x^4+c_{1}})/(\sqrt[3]{4)x}