What is the integral from 0 to 1.2 of (1-y/2) ?

The integral from 0 to 1.2 of (1-y/2) is 0.84

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integral from 0 to 1.2 of (1-y/2)

\int_{0}^{1.2} (1 - \frac{y}{2}) d y

0.84

Solution steps

\int_{0}^{1.2} 1 - \frac{y}{2} d y

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{1.2} 1 d y - \int_{0}^{1.2} \frac{y}{2} d y

\int_{0}^{1.2} 1 d y = 1.2

\int_{0}^{1.2} \frac{y}{2} d y = 0.36

= 1.2 - 0.36

Simplify

= 0.84

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What is the integral from 0 to 1.2 of (1-y/2) ?
The integral from 0 to 1.2 of (1-y/2) is 0.84