What is the derivative of g(x)=x^{2/3} ?

The derivative of g(x)=x^{2/3} is 2/(3x^{1/3)}

What is the first derivative of g(x)=x^{2/3} ?

The first derivative of g(x)=x^{2/3} is 2/(3x^{1/3)}

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derivative of

g (x) = x^{\frac{2}{3}}

\frac{2}{3 x ^{\frac{1}{3}}}

Solution steps

\frac{d}{d x} (x^{\frac{2}{3}})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= \frac{2}{3} x^{\frac{2}{3} - 1}

Simplify

\frac{2}{3} x^{\frac{2}{3} - 1} : \frac{2}{3 x ^{\frac{1}{3}}}

= \frac{2}{3 x ^{\frac{1}{3}}}

\int_{0}^{3} t e^{- 1} d t

e^{- x^{2}}

\frac{d}{d x} (\frac{5 x + 1}{x ^{2} - 3})

\int sin^{4} (x) \cdot cos^{7} (x) d x

\frac{\partial}{\partial y} (x^{2} + y^{2} - 2 x)

What is the derivative of g(x)=x^{2/3} ?
The derivative of g(x)=x^{2/3} is 2/(3x^{1/3)}
What is the first derivative of g(x)=x^{2/3} ?
The first derivative of g(x)=x^{2/3} is 2/(3x^{1/3)}