What is the first derivative of 3x^2+3 ?

The first derivative of 3x^2+3 is 6x

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derivative of 3x^2+3

\frac{d}{d x} (3 x^{2} + 3)

6 x

Solution steps

\frac{d}{d x} (3 x^{2} + 3)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x^{2}) + \frac{d}{d x} (3)

\frac{d}{d x} (3 x^{2}) = 6 x

\frac{d}{d x} (3) = 0

= 6 x + 0

Simplify

= 6 x

\frac{6}{x}

\frac{1}{3 x ^{2} + 1}

n = 1 \sum \infty n^{- \frac{2}{3}}

2 (t - 3)^{2} + 9 (t - 3) + 11

y = 3 e^{4 x} + 6 e^{2 x}