What is the sum from n=1 to infinity of (cos(24))^n ?

The sum from n=1 to infinity of (cos(24))^n is converges

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sum from n=1 to infinity of (cos(24))^n

n = 1 \sum \infty (cos (24))^{n}

converges

Solution steps

n = 1 \sum \infty (cos (24))^{n}

n = k \sum \infty (a_{n}) = n = 0 \sum \infty (a_{n}) - a_{0} - a_{1} - \dots a_{k - 1}

= n = 0 \sum \infty (cos (24))^{n} - (cos (24))^{0}

n = 0 \sum \infty (cos (24))^{n} =

converges

= converges - (cos (24))^{0}

= converges

x \to 0 lim (\frac{x ^{2}}{2} - \frac{2}{x})

f (x) = arccos (\frac{x}{2})

\frac{d}{d y} (x y + y)

(- 5, 5), (3, - 4)

\int (ln (x^{3}))^{2} d x

What is the sum from n=1 to infinity of (cos(24))^n ?
The sum from n=1 to infinity of (cos(24))^n is converges