What is the derivative of ln(x^2-2x) ?

The derivative of ln(x^2-2x) is (2x-2)/(x^2-2x)

What is the first derivative of ln(x^2-2x) ?

The first derivative of ln(x^2-2x) is (2x-2)/(x^2-2x)

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derivative of

ln (x^{2} - 2 x)

\frac{2 x - 2}{x ^{2} - 2 x}

Solution steps

\frac{d}{d x} (ln (x^{2} - 2 x))

Apply the chain rule:

\frac{1}{x ^{2} - 2 x} \frac{d}{d x} (x^{2} - 2 x)

= \frac{1}{x ^{2} - 2 x} \frac{d}{d x} (x^{2} - 2 x)

\frac{d}{d x} (x^{2} - 2 x) = 2 x - 2

= \frac{1}{x ^{2} - 2 x} (2 x - 2)

Simplify

\frac{1}{x ^{2} - 2 x} (2 x - 2) : \frac{2 x - 2}{x ^{2} - 2 x}

= \frac{2 x - 2}{x ^{2} - 2 x}

\int \frac{1}{12 x ^{3}} d x

\int lo g_{2} (x + 2) d x

\int_{0}^{1} e^{x} - 1 d x

\int sin (ln (6 x)) d x

\frac{d}{d x} (2 \cdot 3 x)

What is the derivative of ln(x^2-2x) ?
The derivative of ln(x^2-2x) is (2x-2)/(x^2-2x)
What is the first derivative of ln(x^2-2x) ?
The first derivative of ln(x^2-2x) is (2x-2)/(x^2-2x)