What is the derivative of f(x)=-4x+8 ?

The derivative of f(x)=-4x+8 is -4

What is the first derivative of f(x)=-4x+8 ?

The first derivative of f(x)=-4x+8 is -4

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derivative of

f (x) = - 4 x + 8

- 4

Solution steps

\frac{d}{d x} (- 4 x + 8)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (4 x) + \frac{d}{d x} (8)

\frac{d}{d x} (4 x) = 4

\frac{d}{d x} (8) = 0

= - 4 + 0

Simplify

= - 4

n = 5 \sum \infty \frac{7 ^{n}}{8 ^{n}}

\frac{d y}{d x} = 7^{x} ln (7) + \frac{2}{x ^{2} + 1}

\frac{d ^{3}}{d x ^{3}} (\frac{10}{x ^{2}})

\int (- e^{- x}) d x

\frac{d}{d x} (\frac{x ^{2} - 4}{x ^{2} - 3})

What is the derivative of f(x)=-4x+8 ?
The derivative of f(x)=-4x+8 is -4
What is the first derivative of f(x)=-4x+8 ?
The first derivative of f(x)=-4x+8 is -4