What is the sum from i=0 to infinity of (1/3)^i ?

The sum from i=0 to infinity of (1/3)^i is 3/2

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sum from i=0 to infinity of (1/3)^i

i = 0 \sum \infty (\frac{1}{3})^{i}

\frac{3}{2}

Solution steps

i = 0 \sum \infty (\frac{1}{3})^{i}

Apply Series Geometric Test:

\frac{3}{2}

= \frac{3}{2}

\frac{\partial}{\partial x} (\frac{1}{1 + x ^{2} + y ^{2}})

\frac{d}{d x} (x^{3} + e^{2 x})

x \to 2 lim (x^{2} + 3 x - 1)

\frac{\partial}{\partial x} (\frac{4 x - 6 y}{y ^{2} + 2 x ^{2}})

\frac{d}{d x} (sin (ln (cos (x))))

What is the sum from i=0 to infinity of (1/3)^i ?
The sum from i=0 to infinity of (1/3)^i is 3/2