What is the integral of ln(21t) ?

The integral of ln(21t) is tln(21t)-t+C

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integral of ln(21t)

\int ln (21 t) d t

t ln (21 t) - t + C

Solution steps

\int ln (21 t) d t

Apply Integration By Parts

: t ln (21 t) - \int 1 d t

= t ln (21 t) - \int 1 d t

\int 1 d t = t

= t ln (21 t) - t

Add a constant to the solution

= t ln (21 t) - t + C

f (x) = 2 x^{3} + 3 x^{2} - 12 x + 4, at x = 0

\frac{\partial}{\partial x} (\frac{1}{( x - y )})

\int e^{x + 9 e^{x}} d x

y = 2 x^{\frac{1}{3}}, 0 \leq x \leq 32

4 (3 x + y - 2) d x - (3 x + y) d y = 0