What is the d/(dt)(8t^{3/2}) ?

The d/(dt)(8t^{3/2}) is 12t^{1/2}

What is the first d/(dt)(8t^{3/2}) ?

The first d/(dt)(8t^{3/2}) is 12t^{1/2}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d t} (8 t^{\frac{3}{2}})

12 t^{\frac{1}{2}}

Solution steps

\frac{d}{d t} (8 t^{\frac{3}{2}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 8 \frac{d}{d t} (t^{\frac{3}{2}})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 8 \cdot \frac{3}{2} t^{\frac{3}{2} - 1}

Simplify

8 \cdot \frac{3}{2} t^{\frac{3}{2} - 1} : 12 t^{\frac{1}{2}}

= 12 t^{\frac{1}{2}}

y^{^{''}} + 4 y = csc (2 x)

y^{^{''}} - 4 y^{^{'}} + 4 y = \frac{( e ^{2 x} )}{x ^{2}}

e^{x}, e^{- 4}, 4, 0

\frac{440 t}{( t ^{2} + 7 ) ^{3}}

\int tan^{4} (x) cos^{5} (x) d x